Python调用C/C++程序详解编程语言

 1 #include <stdio.h> 
 2 #include <stdlib.h> 
 3 #include <string.h> 
 4  
 5 class PythonTest{ 
 6 public: 
 7     PythonTest():_is_inited(false), _num(0){ 
 8      
 9     }    
10  
11     int init(int num){ 
12         _num = num; 
13         _is_inited = true; 
14         printf("inited ok/n"); 
15         return 0; 
16     }    
17      
18     int str2(char *src, char* dest, int len){ 
19         if (src == NULL || len <= 0){  
20             return 0; 
21         }    
22  
23         int src_len = strlen(src); 
24         int num = snprintf(dest, len, "%s%s", src, src); 
25         return (num < len -1)? num:0; 
26     }    
27  
28     bool is_inited(){ 
29         printf("_num = %d/n", _num); 
30         return _is_inited; 
31     }    
32  
33 private: 
34     bool _is_inited; 
35     int _num; 
36 };

 1 #include "pycall.h" 
 2  
 3 extern "C" { 
 4  
 5 PythonTest py;  
 6  
 7 int init(int num){ 
 8     return py.init(num); 
 9 } 
10  
11 bool is_inited(){ 
12     return py.is_inited(); 
13 } 
14  
15 int str2(char* src, char* dest, int len){ 
16     return py.str2(src, dest, len); 
17 } 
18  
19 int add(int a, int b){  
20     return a + b; 
21 } 
22  
23 }

 1 #coding=utf-8 
 2  
 3 import ctypes  
 4 from ctypes import * 
 5  
 6 ##加载库文件 
 7 ll = ctypes.cdll.LoadLibrary   
 8 lib = ll("./libpycall.so")    
 9  
10 ##call 
11 fun=lib.init    ###类似C/C++函数指针 
12 fun.restype = c_int ##设置函数返回值类型 
13 print fun(8); 
14 print "*" * 20 
15  
16 ##call 
17 fun=lib.is_inited 
18 fun.restype = c_bool 
19 print fun(); 
20 print "*" * 20 
21  
22 ##call 
23 fun=lib.str2 
24 src = "hello world " 
25 dest = "*" * 30     ###申请buf, 用于保存返回结果  
26 num = fun(src, dest, len(dest)) ###传递指针作为参数 
27 if num != 0: 
28     print dest[:num] 
29 else: 
30     print "buf is not ok" 
31 print "*" * 20 
32  
33 ##call 
34 print lib.add(1, 2);  
35 print "*" * 20