Java经典实例：正则表达式，找到匹配的文本详解编程语言

import java.util.regex.Matcher; 
import java.util.regex.Pattern; 
 
/** 
 * Created by Frank 
 */ 
public class REMatch { 
    public static void main(String[] args) { 
        String patt = "Q[^u]//d+//."; 
        Pattern r = Pattern.compile(patt); 
        String line = "Order QT300. Now! QT400."; 
        Matcher m = r.matcher(line); 
        int i = 0; 
        while (m.find()) { 
            // group(0)或group()将会返回整个匹配的字符串（完全匹配）；group(i)则会返回与分组i匹配的字符 
            // 这个例子只有一个分组 
            System.out.println(patt + " matches /"" + m.group(0) + "/" in /"" + line + "/""); 
            System.out.println("start:" + m.start() + " end:" + m.end()); 
        } 
    } 
}

Q[^u]/d+/. matches "QT300." in "Order QT300. Now! QT400." 
start:6 end:12 
Q[^u]/d+/. matches "QT400." in "Order QT300. Now! QT400." 
start:18 end:24

import java.util.regex.Matcher; 
import java.util.regex.Pattern; 
 
/** 
 * Created by Frank 
 */ 
public class REMatchTwoFields { 
    public static void main(String[] args) { 
        String inputLine = "Adams,John Quincy"; 
        Pattern r = Pattern.compile("(.*),(.*)"); 
        Matcher m = r.matcher(inputLine); 
        if (!m.matches()) { 
            throw new IllegalArgumentException("Bad Input"); 
        } 
        // 分组0得到的是整个原字符串 
        for (int i = 0; i < m.groupCount() + 1; i++) { 
            System.out.println("分组" + i + ":" + m.group(i)); 
        } 
    } 
}

分组0:Adams,John Quincy 
分组1:Adams 
分组2:John Quincy