Java判断一个时间是否在时间区间内详解编程语言

package com.liying.tiger.test; 
 
import java.text.ParseException; 
import java.text.SimpleDateFormat; 
import java.util.Calendar; 
import java.util.Date; 
 
public class Test { 
    public static void main(String[] args) throws ParseException { 
        String format = "HH:mm:ss"; 
        Date nowTime = new SimpleDateFormat(format).parse("09:27:00"); 
        Date startTime = new SimpleDateFormat(format).parse("09:27:00"); 
        Date endTime = new SimpleDateFormat(format).parse("09:27:59"); 
        System.out.println(isEffectiveDate(nowTime, startTime, endTime)); 
    } 
 
    /** 
     * 判断当前时间是否在[startTime, endTime]区间，注意时间格式要一致 
     *  
     * @param nowTime 当前时间 
     * @param startTime 开始时间 
     * @param endTime 结束时间 
     * @return 
     * @author jqlin 
     */ 
    public static boolean isEffectiveDate(Date nowTime, Date startTime, Date endTime) { 
        if (nowTime.getTime() == startTime.getTime() 
                || nowTime.getTime() == endTime.getTime()) { 
            return true; 
        } 
 
        Calendar date = Calendar.getInstance(); 
        date.setTime(nowTime); 
 
        Calendar begin = Calendar.getInstance(); 
        begin.setTime(startTime); 
 
        Calendar end = Calendar.getInstance(); 
        end.setTime(endTime); 
 
        if (date.after(begin) && date.before(end)) { 
            return true; 
        } else { 
            return false; 
        } 
    } 
}