fastjson如何去掉多余的反斜杠详解编程语言

{"data":"{/"message/":/"/",/"result/":0,/"data/":{/"cardtype/":0,/"sealimgs/":[/"{
  ///"id///":16,///"img///":///"H4znOvV8Cb101BRlW6WhIU8n8B6GEqjM44AAA=/",/"realnameauthstate/":3,/"country/":0,/"faceacstate/":0,/"email/":/"[email protected]/",/"dateformat/":0,/"signimgtype/":/"png/",/"company/":/"/",/"realname/":/"张三/",/"uafacstate/":0}}","mac":"f17d652444ce014c0c9cc58aff0b79bdffbe90b4"}  

最近在做一个项目，用的了阿里的fastjson，但是返回的json串中有许多反斜杠，都要被他烦死了（///），查了半天，终于解决了，具体方法如下：

import java.util.ArrayList;   
import java.util.List;   
   
import com.alibaba.fastjson.JSONObject;   
   
public class Main {   
   public static void main(String[] argv) throws Exception {   
       List<A> a = new ArrayList<A>() ;   
       a.add(new A("1", 1)) ;   
       a.add(new A("2", 2)) ;   
       a.add(new A("3", 3)) ;   
	 //直接返回对象就不会有反斜杠。。 
	         Object o = JSONObject.toJSON(a) ;   
	         System.out.println(o) ;   
	     }   
	 }   
	   
	   
	   
	class A{   
	    String name ;   
	    Integer age ;    
	   A(String name , Integer age){   
	        this.name = name ;   
	        this.age = age ;   
	     }   
	    public String getName() {   
	        return name;   
	     }   
	    public void setName(String name) {   
	         this.name = name;   
	      }   
	    public Integer getAge() {   
	        return age;   
	     }   
	    public void setAge(Integer age) {   
	        this.age = age;   
	    }   
	        
	   }  

直接返回对象就不会有反斜杠了，我的程序是这样的

JSONArray sealimgs = new JSONArray(userImg_seals.size()); 
                int i = 0; 
                for(UserImg userImgSub : userImg_seals){ 
                    byte[] imgdata = userImgSub.getImgdata(); 
                    byte[] comp_imgdata = CompressUtil.compressData(imgdata); 
                    sealimg = Base64.encodeBytes(comp_imgdata); 
                    sealimgname = userImgSub.getImgname(); 
                    if (StrTool.strNotNull(sealimgname)) { 
                        sealimgname = sealimgname.substring(sealimgname.lastIndexOf(".") + 1, sealimgname.length()); 
                    } 
                    JSONObject subJson = new JSONObject(); 
                    subJson.put("id", userImgSub.getImgid()); 
                    subJson.put("type", sealimgname); 
                    subJson.put("img", sealimg); 
                    sealimgs.add(subJson); 
                    i++; 
                } 
                Object obj = JSONObject.toJSON(sealimgs);