Python/Shell 正则表达式与运用详解程序员

1 #!/bin/bash 
2  
3 str="date:2017-11-28 os:centos blackbord:blog" 
4  
5 echo $str | grep centos --color 
6 echo $str | grep -oE centos --color 
7 #组的使用 
8 echo $str | sed -rne 's/.*(date:[0-9]{4}-[0-9]{2}-[0-9]{2}).*(blackbord:[a-z]+).*/group:/1 group:/2/p'

1 date:2017-11-28 os:centos blackbord:blog 
2 centos 
3 group:date:2017-11-28 group:blackbord:blog

 1 #coding=utf-8 
 2 import re 
 3  
 4 str1="line:20 date(2017-11-28) os:centos blackbord[blog] last" 
 5  
 6 matchobj = re.search("(date/(/d+-/d+-/d+/)).*(os:[a-z]+).*(blackbord/[[a-z]+/])", str1) 
 7 if matchobj: 
 8     num = len(matchobj.groups()) 
 9     print "match_len:" + str(num) 
10     print matchobj.groups() 
11  
12     date = matchobj.group(1)    #date(2017-11-28) 
13     date = date[5:len(date)-1] 
14     os = matchobj.group(2)  #os:centos 
15     os = os[3:] 
16     blackbord = matchobj.group(3)   #blackbord[blog] 
17     blackbord = blackbord[10:len(blackbord) -1 ] 
18     print("date:%s/nos:%s/nblackbord:%s" % (date, os, blackbord)) 
19 else: 
20     print "not match str1"

1 match_len:3 
2 ('date(2017-11-28)', 'os:centos', 'blackbord[blog]') 
3 date:2017-11-28 
4 os:centos 
5 blackbord:blog