Source
Find the Nth number in Fibonacci sequence. A Fibonacci sequence is defined as follow: The first two numbers are 0 and 1. The i th number is the sum of i-1 th number and i-2 th number. The first ten numbers in Fibonacci sequence is: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34 ... Example Given 1, return 0 Given 2, return 1 Given 10, return 34 Note The Nth fibonacci number won't exceed the max value of signed 32-bit integer in the test cases.
题解
斐波那契数列使用递归极其容易实现,其实使用非递归的方法也很容易,不断向前滚动即可。
Java
class Solution { /** * @param n: an integer * @return an integer f(n) */ public int fibonacci(int n) { if (n < 0) return -1; if (n == 1) return 0; if (n == 2) return 1; int fn = 0, fn1 = 1, fn2 = 0; for (int i = 3; i <= n; i++) { fn = fn1 + fn2; fn2 = fn1; fn1 = fn; } return fn; } }
源码分析
- corner cases
- 初始化 fn, fn1, fn2, 建立地推关系。
- 注意 fn, fn2, fn1的递推顺序。
复杂度分析
遍历一次,时间复杂度为 O(n), 使用了两个额外变量,空间复杂度为 O(1).
原创文章,作者:奋斗,如若转载,请注明出处:https://blog.ytso.com/20708.html