Sharding JDBC分表怎么配置

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分表配置

由于的单库分表,所以只配置一个数据源就可以了

#配置数据源
spring.shardingsphere.datasource.names=test0
#test0
spring.shardingsphere.datasource.test0.type=com.zaxxer.hikari.HikariDataSource
spring.shardingsphere.datasource.test0.driver-class-name=com.mysql.cj.jdbc.Driver
spring.shardingsphere.datasource.test0.jdbcUrl=jdbc:mysql://127.0.0.1:3306/test0
spring.shardingsphere.datasource.test0.username=devadmin
spring.shardingsphere.datasource.test0.password=

设置绑定表

# 设置绑定表
spring.shardingsphere.sharding.binding-tables[0]=health_record,health_task

设置分表的策略

这里根据 record_id 奇偶来分表的。分为 health_record0,health_record1 和 health_task0,health_task1

# health_record
spring.shardingsphere.sharding.tables.health_record.actual-data-nodes=test0.health_record$->{0..1}
spring.shardingsphere.sharding.tables.health_record.table-strategy.inline.algorithm-expression=health_record$->{record_id % 2}
spring.shardingsphere.sharding.tables.health_record.table-strategy.inline.sharding-column=record_id
spring.shardingsphere.sharding.tables.health_record.key-generator.column=record_id
spring.shardingsphere.sharding.tables.health_record.key-generator.type=SNOWFLAKE
# health_task
spring.shardingsphere.sharding.tables.health_task.actual-data-nodes=test0.health_task$->{0..1}
spring.shardingsphere.sharding.tables.health_task.table-strategy.inline.algorithm-expression=health_task$->{record_id %2}
spring.shardingsphere.sharding.tables.health_task.table-strategy.inline.sharding-column=record_id
spring.shardingsphere.sharding.tables.health_task.key-generator.column=task_id
spring.shardingsphere.sharding.tables.health_task.key-generator.type=SNOWFLAKE

完整配置

server.port=8080
#打印sql
spring.shardingsphere.props.sql.show=true
#配置数据源
spring.shardingsphere.datasource.names=test0
#test0
spring.shardingsphere.datasource.test0.type=com.zaxxer.hikari.HikariDataSource
spring.shardingsphere.datasource.test0.driver-class-name=com.mysql.cj.jdbc.Driver
spring.shardingsphere.datasource.test0.jdbcUrl=jdbc:mysql://127.0.0.1:3306/test0
spring.shardingsphere.datasource.test0.username=devadmin
spring.shardingsphere.datasource.test0.password=


# 设置绑定表
spring.shardingsphere.sharding.binding-tables[0]=health_record,health_task
# health_record
spring.shardingsphere.sharding.tables.health_record.actual-data-nodes=test0.health_record$->{0..1}
spring.shardingsphere.sharding.tables.health_record.table-strategy.inline.algorithm-expression=health_record$->{record_id % 2}
spring.shardingsphere.sharding.tables.health_record.table-strategy.inline.sharding-column=record_id
spring.shardingsphere.sharding.tables.health_record.key-generator.column=record_id
spring.shardingsphere.sharding.tables.health_record.key-generator.type=SNOWFLAKE
# health_task
spring.shardingsphere.sharding.tables.health_task.actual-data-nodes=test0.health_task$->{0..1}
spring.shardingsphere.sharding.tables.health_task.table-strategy.inline.algorithm-expression=health_task$->{record_id %2}
spring.shardingsphere.sharding.tables.health_task.table-strategy.inline.sharding-column=record_id
spring.shardingsphere.sharding.tables.health_task.key-generator.column=task_id
spring.shardingsphere.sharding.tables.health_task.key-generator.type=SNOWFLAKE

数据库如下

Sharding JDBC分表怎么配置

health_level 数据如下

Sharding JDBC分表怎么配置

user数据如下

Sharding JDBC分表怎么配置

health_record0,health_record1

health_record0 中 record_id 都是偶数 ,health_record1 都是奇数

Sharding JDBC分表怎么配置 Sharding JDBC分表怎么配置

health_task0,health_task1

health_task0 中 record_id 都是偶数 ,health_task1 都是奇数

Sharding JDBC分表怎么配置 Sharding JDBC分表怎么配置

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原创文章,作者:306829225,如若转载,请注明出处:https://blog.ytso.com/230333.html

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