现有两表A，B
A表存储商品点击日志，B表存储商品
要求显示当天所有商品点击量列表并附带总数并按天排序
复制代码 代码如下:
declare @sql varchar(2000)
set @sql=’select CONVERT(varchar(100), a.[Time], 23) as 时间,count(b.title) as 总数’
select @sql =@sql+ ‘,sum(case b.title when ”’+Title+”’ then 1 else 0 end) as ‘+'[‘+Title+’]’
from (select distinct title from B) as B
set @sql=@sql+’ from A as a left join B as b on a.AId=B.Aid
group by CONVERT(varchar(100), a.[Time], 23) order by CONVERT(varchar(100), a.[Time], 23) desc’
exec(@sql)
显示结果
| 时间 | 总数 | 商品1 | 商品2 | 商品3 |
| 2013-11-11 | 5 | 1 | 0 | 4 |
| 2013-11-10 | 13 | 2 | 11 | 1 |
原创文章，作者：3628473679，如若转载，请注明出处：https://blog.ytso.com/234699.html