思路：遍历链表，通过数组来存储读取到的value，最终逆序输出

Python：

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution:
    def reversePrint(self, head: ListNode) -> List[int]:
        res=[]
        while head:
            res.append(head.val)
            head=head.next
        return res[::-1]