将年龄转换为天数并显示两个值

#include <stdio.h>  
int main(void) {  
    int ageyears;    /* age in years */  
    int agedays;    /* age in days  */  
                    //from  w  w  w .yi ib ai .c  o m
    ageyears = 101;  
    agedays = 365 * ageyears;  
    printf("An age of %d years is %d days./n", ageyears, agedays);  
    return 0;  
}