对int类型变量和输出结果进行数学计算

#include <stdio.h>
#include <stdlib.h>
int main()
{
   int contributed;
   int received;
   contributed = 65 - 19;
   received = 969 - 65;
   printf("for %i years./n", contributed);
   printf("for %i years./n", received);
   return(0);
}