使用条件表达式将大写字母转换为小写字母

#include <stdio.h>

int lower(int c);

int main(void){
    char s[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
    int i = 0;
    while (s[i] != '/0') {
        printf("%c -> %c/n", s[i], lower(s[i]));
        i++;
    }
    return 0;
}

int lower(int c){
    return (c >= 'A' && c<= 'Z') ? c + 'a' - 'A' : c;
}