#include <stdio.h>
int main(void){
char ch;//
int i;
float fl;
fl = i = ch = 'C';
printf("ch = %c, i = %d, fl = %2.2f/n", ch, i, fl);
ch = ch + 1;
i = fl + 4 * ch;
fl = 2.0 * ch + i;
printf("ch = %c, i = %d, fl = %2.2f/n", ch, i, fl);
ch = 107;
printf("Now ch = %c/n", ch);
ch = 81.89;
printf("Now ch = %c/n", ch);
return 0;
}
原创文章,作者:ItWorker,如若转载,请注明出处:https://blog.ytso.com/266755.html