猜一下矩阵中的数字

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int random(int m, int n);

int main() {//
  int try1, maxTries, numProblems, answer, response;
  int num1, num2;

  numProblems = 5;
  maxTries = 5;

  srand(time(0));

  for (int h = 1; h <= numProblems; h++) {
    num1 = random(10, 99);
    num2 = random(10, 99);
    answer = num1 + num2;
    for (try1 = 1; try1 <= maxTries; try1++) {
      printf("/nProblem %d, Try %d of %d/n", h, try1, maxTries);
      printf("%5d + %2d = ", num1, num2);
      scanf("%d", &response);
      if (response == answer) {
        printf("Correct, well done!/n");
        break;
      }
      if (try1 < maxTries)
        printf("Incorrect, try again/n");
      else
        printf("Sorry, answer is %d/n", answer);
    }
  }
}

int random(int m, int n) {
  int offset = rand() / (RAND_MAX + 1.0) * (n - m + 1);
  return m + offset;
}

原创文章,作者:ItWorker,如若转载,请注明出处:https://blog.ytso.com/266768.html

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