在网上找了很久,终于解决了,代码如下:
with mydata as (
select
ID,
my_array
from
(
--some array<struct> example
select
1 ID,
array(1.1, 2.2, 3.3) as my_array
union all
select
2 ID,
array(4.4, 5.5, 6.6) as my_array
) s
)
select
ID,
concat_ws(',', collect_list(element)) as my_string --collect array of strings and concatenate it using ',' delimiter
from
(
select
s.ID,
cast(mystruct as string) as element --concatenate struct using : as a delimiter Or concatenate in some other way
from
mydata s lateral view explode(s.my_array) a as mystruct
) s
group by
ID;
结果示意图:
id my_string
2 4.4,5.5,6.6
1 1.1,2.2,3.3
原创文章,作者:kirin,如若转载,请注明出处:https://blog.ytso.com/267395.html