关于 ios：不能将值类型”TableViewController.Type”转换为预期的参数类型”UIViewController”

cannot covert value type ‘TableViewController.Type’ to expected argument type ‘UIViewController’

我正在制作一个注册和登录的应用程序。我为此使用了 Parse。如果登录/注册成功，我想将视图控制器移动到 TableViewController。但是我收到此错误：”无法将值类型//’TableViewController.Type//’ 转换为预期的参数类型//’UIViewController//’。

这是我收到错误的行：

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func logInViewController(logInController: PFLogInViewController, didLogInUser user: PFUser) {
self.dismissViewControllerAnimated(true, completion: nil)
self.presentViewController(TimelineTableViewController, animated: true, completion: nil)

}

这是完整的代码：

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// Created by Ojas Sethi on 12/10/15.
// Copyright ? 2015 Jell Apps. All rights reserved.
//

import UIKit
import Parse
import ParseUI

class LoginSignupViewController: UIViewController, PFLogInViewControllerDelegate, PFSignUpViewControllerDelegate {
var logInViewController: PFLogInViewController = PFLogInViewController()
var signUpViewController: PFSignUpViewController = PFSignUpViewController()

override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
}

override func viewDidAppear(animated: Bool) {
super.viewDidAppear(animated)

if (PFUser.currentUser() == nil){
self.logInViewController.fields = PFLogInFields.UsernameAndPassword
self.logInViewController.fields = PFLogInFields.LogInButton
self.logInViewController.fields = PFLogInFields.SignUpButton
self.logInViewController.fields = PFLogInFields.PasswordForgotten
self.logInViewController.fields = PFLogInFields.DismissButton

/*| PFLogInFields.LogInButton | PFLogInFields.SignUpButton | PFLogInFields.PasswordForgotten | PFLogInFields.DismissButton*/

let logoInLogoTitle = UILabel()
logoInLogoTitle.text ="Ziffer"
logoInLogoTitle.font = UIFont.systemFontOfSize(25)

self.logInViewController.logInView?.logo = logoInLogoTitle
self.logInViewController.delegate = self

let signUpLogoTitle = UILabel()
signUpLogoTitle.text ="Ziffer"
logoInLogoTitle.font = UIFont.systemFontOfSize(25)

self.signUpViewController.signUpView?.logo = signUpLogoTitle
self.signUpViewController.delegate = self
self.logInViewController.signUpController = self.signUpViewController
}
}

override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
func logInViewController(logInController: PFLogInViewController, shouldBeginLogInWithUsername username: String, password: String) -> Bool {
if (!username.isEmpty || !password.isEmpty){
return true
}else{
return false
}
}

func logInViewController(logInController: PFLogInViewController, didFailToLogInWithError error: NSError?) {
print("failed to login")
}

func signUpViewController(signUpController: PFSignUpViewController, didSignUpUser user: PFUser) {
self.dismissViewControllerAnimated(true, completion: nil)
self.presentViewController(logInViewController, animated: true, completion: nil)
SignUpSuccessfulAlert()

}

func signUpViewController(signUpController: PFSignUpViewController, didFailToSignUpWithError error: NSError?) {
print("Failed to signup…")

SignUpFaliedAlert()
}

func signUpViewControllerDidCancelSignUp(signUpController: PFSignUpViewController) {
print("User dismissed sign up.")
}

func SignUpSuccessfulAlert(){
var alertController : UIAlertController
alertController = UIAlertController(title:"Sign Up Successful", message:"Yay! Sign up was successful! Now you can start using Ziffer!", preferredStyle: .Alert)

let doneAction = UIAlertAction(title:"Ok", style: .Default, handler: nil)

alertController.addAction(doneAction)

self.presentViewController(alertController, animated: true, completion: nil)
}

func SignUpFaliedAlert(){
var signUpalertFail : UIAlertController

signUpalertFail = UIAlertController(title:"Failed", message:"Sorry! Sign up faield. Check the connections and try again later", preferredStyle: .Alert)

let okAction = UIAlertAction(title:"Ok", style: .Default, handler: nil)

signUpalertFail.addAction(okAction)

self.presentViewController(signUpalertFail, animated: true, completion: nil)
}
}

首先，您尝试从即将关闭的登录视图控制器中展示您的新视图控制器。那是不对的。您可能希望从提供登录视图控制器的稳定视图控制器中呈现它。这是关于如何做到这一点的好例子。这是基于objective-c的，所以请耐心等待。

其次，您需要创建一个 TimelineTableViewController 对象以显示在视图层次结构中(再次查看我在上面共享的链接)。像这样的东西：

1 2	let timeLineTableVC = TimelineTableViewController() self.presentViewController(timeLineTableVC, animated: true, completion: nil)

您的(大写) TimelineTableViewController 似乎是一个类，而不是一个类实例。您需要首先创建此控制器的实例。

推荐的方法是在情节提要中为此控制器创建一个segue，然后在您想要呈现控制器时调用performSegueWithIdentifier。

最接近您的代码的方法是使用 instantiateViewControllerWithIdentifier 在代码中(再次：从情节提要)实例化视图控制器，但上述方法代码较少，做同样的事情，因此是首选。

原创文章，作者：ItWorker，如若转载，请注明出处：https://blog.ytso.com/268645.html

关于 ios：不能将值类型”TableViewController.Type”转换为预期的参数类型”UIViewController”

cannot covert value type ‘TableViewController.Type’ to expected argument type ‘UIViewController’

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