buildroot file system & cross compiling: dynamically linked application fails but static ok. How to link against uClibc
我有一个 buildroot 创建的文件系统，我正在尝试在 lighttpd 服务器上执行一些 c 代码。
我创建了一个简单的 C 模块，它只打印出几行 html。代码如下所示：
1 2 3 4 5 6 7 8 9 10 | #include"stdio.h" int main(void) { |
我正在使用来自 Ubuntu 存储库的编译器来编译它
但是在没有静态标志的情况下编译，执行失败如下：
1 2 | # ./test.cgi –sh: ./first.cgi: not found |
我想知道原因是否是 c 库错误，我应该链接到由 buildroot 编译的 uClibc。
在我的 buildroot 文件夹
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 | –rwxr–xr–x 1 jlumme jlumme 25444 Jan 26 17:13 ld–uClibc–0.9.33.2.so lrwxrwxrwx 1 jlumme jlumme 21 Jan 26 17:12 ld–uClibc.so.0 –> ld–uClibc–0.9.33.2.so –rwxr–xr–x 1 jlumme jlumme 13191 Jan 26 17:13 libcrypt–0.9.33.2.so lrwxrwxrwx 1 jlumme jlumme 20 Jan 26 17:13 libcrypt.so.0 –> libcrypt–0.9.33.2.so lrwxrwxrwx 1 jlumme jlumme 21 Jan 26 17:13 libc.so.0 –> libuClibc–0.9.33.2.so –rwxr–xr–x 1 jlumme jlumme 13383 Jan 26 17:13 libdl–0.9.33.2.so lrwxrwxrwx 1 jlumme jlumme 17 Jan 26 17:13 libdl.so.0 –> libdl–0.9.33.2.so –rw–r—r— 1 jlumme jlumme 135 Jan 26 17:15 libgcc_s.so –rw–r—r— 1 jlumme jlumme 180152 Jan 26 17:15 libgcc_s.so.1 –rwxr–xr–x 1 jlumme jlumme 64555 Jan 26 17:13 libm–0.9.33.2.so lrwxrwxrwx 1 jlumme jlumme 16 Jan 26 17:13 libm.so.0 –> libm–0.9.33.2.so –rwxr–xr–x 1 jlumme jlumme 4772 Jan 26 17:13 libnsl–0.9.33.2.so lrwxrwxrwx 1 jlumme jlumme 18 Jan 26 17:13 libnsl.so.0 –> libnsl–0.9.33.2.so –rwxr–xr–x 1 jlumme jlumme 79059 Jan 26 17:13 libpthread–0.9.33.2.so lrwxrwxrwx 1 jlumme jlumme 22 Jan 26 17:13 libpthread.so.0 –> libpthread–0.9.33.2.so –rwxr–xr–x 1 jlumme jlumme 4776 Jan 26 17:13 libresolv–0.9.33.2.so lrwxrwxrwx 1 jlumme jlumme 21 Jan 26 17:13 libresolv.so.0 –> libresolv–0.9.33.2.so –rwxr–xr–x 1 jlumme jlumme 13927 Jan 26 17:13 librt–0.9.33.2.so lrwxrwxrwx 1 jlumme jlumme 17 Jan 26 17:13 librt.so.0 –> librt–0.9.33.2.so –rwxr–xr–x 1 jlumme jlumme 284451 Jan 26 17:13 libuClibc–0.9.33.2.so –rwxr–xr–x 1 jlumme jlumme 4955 Jan 26 17:13 libutil–0.9.33.2.so lrwxrwxrwx 1 jlumme jlumme 19 Jan 26 17:13 libutil.so.0 –> libutil–0.9.33.2.so |
是我正在寻找的
我怎样才能将我的应用程序与它联系起来？
在我的目标板上，我可以在
中看到这个
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 | lrwxrwxrwx 1 root root 15 Jan 26 2013 libbz2.so –> libbz2.so.1.0.6 lrwxrwxrwx 1 root root 15 Jan 26 2013 libbz2.so.1 –> libbz2.so.1.0.6 lrwxrwxrwx 1 root root 15 Jan 26 2013 libbz2.so.1.0 –> libbz2.so.1.0.6 –rwxrwxr–x 1 root root 57924 Jan 26 2013 libbz2.so.1.0.6 lrwxrwxrwx 1 root root 16 Jan 26 2013 libelf.so –> libelf.so.0.8.12 lrwxrwxrwx 1 root root 16 Jan 26 2013 libelf.so.0 –> libelf.so.0.8.12 –rwxr–xr–x 1 root root 69924 Jan 26 2013 libelf.so.0.8.12 lrwxrwxrwx 1 root root 16 Jan 26 2013 libpcre.so –> libpcre.so.1.0.0 lrwxrwxrwx 1 root root 16 Jan 26 2013 libpcre.so.1 –> libpcre.so.1.0.0 –rwxr–xr–x 1 root root 88804 Jan 26 2013 libpcre.so.1.0.0 lrwxrwxrwx 1 root root 19 Jan 26 2013 libpcrecpp.so –> libpcrecpp.so.0.0.0 lrwxrwxrwx 1 root root 19 Jan 26 2013 libpcrecpp.so.0 –> libpcrecpp.so.0.0.0 –rwxr–xr–x 1 root root 27436 Jan 26 2013 libpcrecpp.so.0.0.0 lrwxrwxrwx 1 root root 21 Jan 26 2013 libpcreposix.so –> libpcreposix.so.0.0.0 lrwxrwxrwx 1 root root 21 Jan 26 2013 libpcreposix.so.0 –> libpcreposix.so.0.0.0 –rwxr–xr–x 1 root root 5576 Jan 26 2013 libpcreposix.so.0.0.0 lrwxrwxrwx 1 root root 19 Jan 26 2013 libsqlite3.so –> libsqlite3.so.0.8.6 lrwxrwxrwx 1 root root 19 Jan 26 2013 libsqlite3.so.0 –> libsqlite3.so.0.8.6 –rwxr–xr–x 1 root root 516472 Jan 26 2013 libsqlite3.so.0.8.6 lrwxrwxrwx 1 root root 19 Jan 26 2013 libstdc++.so –> libstdc++.so.6.0.14 lrwxrwxrwx 1 root root 19 Jan 26 2013 libstdc++.so.6 –> libstdc++.so.6.0.14 –rwxr–xr–x 1 root root 418936 Jan 26 2013 libstdc++.so.6.0.14 –rw–r—r— 1 root root 2422 Jan 26 2013 libstdc++.so.6.0.14–gdb.py lrwxrwxrwx 1 root root 16 Jan 26 2013 libxml2.so –> libxml2.so.2.8.0 lrwxrwxrwx 1 root root 16 Jan 26 2013 libxml2.so.2 –> libxml2.so.2.8.0 –rwxr–xr–x 1 root root 1063556 Jan 26 2013 libxml2.so.2.8.0 drwxrwxr–x 2 root root 4096 Jan 26 2013 lighttpd –rw–r—r— 1 root root 195 Jan 26 2013 xml2Conf.sh |
要构建您的应用程序，您必须使用 Buildroot 生成的交叉编译器，位于
在这里，您使用的是 Ubuntu ARM 交叉编译器，它针对使用
只需使用 Buildroot 为您生成的交叉编译器即可。
原创文章，作者：ItWorker，如若转载，请注明出处：https://blog.ytso.com/268904.html