/* 目录: 一 C原理 二 汇编原理 */
一 C原理
void change(int** p2) { printf("p2 = 0x%x, *p2 = 0x%x/n", p2, *p2); printf("*p2 = 0x%x, *8p2 = %d/n", *p2, **p2); } int main() { int i = 3; printf("&i = 0x%x, i = %d/n", &i, i); int *p = &i; printf("p = 0x%x, *p = %d, &p = 0x%x/n", p, *p, &p); change(&p); return 0; } /* // result &i = 0x293cfba4, i = 3 p = 0x293cfba4, *p = 3, &p = 0x293cfbc8 p2 = 0x293cfbc8, *p2 = 0x293cfba4 *p2 = 0x293cfba4, *8p2 = 3 */
/* 内存: 数值; 地址(数值所在的内存单元编号)。 方法: (1) &p: 取该p变量的地址。 (2) *p: 把p当做某个地址看。 取该p地址里面的值。 思考: 1 *P: 得到数值可能是数值或指针。 2 为什么可以跨函数修改数值内容,因为传递的是内存地址,不受函数作用域影响。 */
二 汇编原理
; 汇编 void change(int** p2) { printf("p2 = 0x%x, *p2 = 0x%x/n", p2, *p2); 00007FF623E224FF mov rax,qword ptr [p2] 00007FF623E22506 mov r8,qword ptr [rax] ; 数值: *p2 00007FF623E22509 mov rdx,qword ptr [p2] ; 数值: p2 00007FF623E22510 lea rcx,[string "p2 = 0x%x, *p2 = 0x%x/n" (07FF623E2BC10h)] 00007FF623E22517 call printf (07FF623E2124Eh) printf("*p2 = 0x%x, *8p2 = %d/n", *p2, **p2); 00007FF623E2251C mov rax,qword ptr [p2] 00007FF623E22523 mov rax,qword ptr [rax] 00007FF623E22526 mov r8d,dword ptr [rax] ; 数值: **p2 00007FF623E22529 mov rax,qword ptr [p2] 00007FF623E22530 mov rdx,qword ptr [rax] ; 数值: *p2 00007FF623E22533 lea rcx,[string "*p2 = 0x%x, *8p2 = %d/n" (07FF623E2BCE0h)] 00007FF623E2253A call printf (07FF623E2124Eh) } int main() { int i = 3; 00007FF623E2211D mov dword ptr [i],3 printf("&i = 0x%x, i = %d/n", &i, i); 00007FF623E22124 mov r8d,dword ptr [i] ; 数值: i 00007FF623E22128 lea rdx,[i] ; 数值: &i 00007FF623E2212C lea rcx,[string "&i = 0x%x, i = %d/n" (07FF623E2BCF8h)] 00007FF623E22133 call printf (07FF623E2124Eh) int *p = &i; 00007FF623E22138 lea rax,[i] ; 数值: &i 00007FF623E2213C mov qword ptr [p],rax ; 数值: p = &i printf("p = 0x%x, *p = %d, &p = 0x%x/n", p, *p, &p); 00007FF623E22140 lea r9,[p] ; 数值: &p 00007FF623E22144 mov rax,qword ptr [p] ; 00007FF623E22148 mov r8d,dword ptr [rax] ; 数值: *p 00007FF623E2214B mov rdx,qword ptr [p] ; 数值: p 00007FF623E2214F lea rcx,[string "p = 0x%x, *p = %d, &p = 0x%x/n" (07FF623E2BD10h)] 00007FF623E22156 call printf (07FF623E2124Eh) change(&p); 00007FF623E2215B lea rcx,[p] ; 数值: &p 00007FF623E2215F call change (07FF623E21532h) return 0; 00007FF623E22164 xor eax,eax }
/* 分析: 查看汇编指令和上面C原理一模一样。 */
原创文章,作者:dweifng,如若转载,请注明出处:https://blog.ytso.com/270676.html