Oracle常用sql

一对多查询

listagg() with group()

listagg(colName,’,’) within group(order by t.colName)查询从表，在每个分组内，LISTAGG根据order by子句对列进行排序，将排序后的结果以指定字符拼接起来

select listagg(t.code_name,',') within group(order by t.code_value) as education 
from code_value t
where t.code_type = 'AAC011'

判断查询

decode

decode(条件,值1,返回值1,值2,返回值2,…值n,返回值n,缺省值)

日期

根据生日查询年龄

select floor(months_between(sysdate,to_date('1995-09-26 00:00:00','yyyy-MM-dd hh24:mi:ss'))/12) as age 
from dual;