移动零

/*
leetCode -- 移动零
 */
public class Remove_zero {
    public static void main(String[] args) {
        Solution solution = new Solution();
        int[] number = new int[]{0,1,0,3,12};
        solution.moveZeroes(number);
    }
}

上面是测试
//--------------------------------------------------
下面是封装的方法

/**
 * 输入: nums = [0,1,0,3,12]
 * 输出: [1,3,12,0,0]
 * <p>
 * 输入: nums = [0]
 * 输出: [0]
 */
class Solution {
    public void moveZeroes(int[] nums) {
        if(nums.length == 0 || nums == null){
            return;
        }
        int[] temp = new int[nums.length];
        int t = 0;   //  < --指针
        for (int i = 0; i < nums.length; i++) {
            if (nums[i] != 0) {
                temp[t] = nums[i];
                t++;
            }
        }
        int number = 0;
        for (int i : temp) {
            if(i == 0){
                number++;
            }
        }
        for (int w = 0; w < temp.length - 1 - number; w++) {
            for (int i = 0; i > temp.length - 1 - w ; i++) {
                if (temp[i] > temp[i + 1]) {
                    int exchange = temp[i];
                    temp[i] = temp[i + 1];
                    temp[i + 1] = exchange;
                }
            }
        }
        System.out.println(Arrays.toString(temp));
    }
}

解析：

用n和t两个指针，来移动，所谓的”指针”就是定义出来的一个数，在循环中跳动，和++的操作