public static void main(String[] args) {
//创建一个二维数组 11*11 0 没有棋子 1黑子 2白子
int[][] array = new int[11][11];
array[1][2]=1;
array[2][3]=2;
//输出原始数组
System.out.println("输出原始数组");
for (int[] ints : array){
for (int anInt : ints) {
System.out.print(anInt+"/t");
}
System.out.println();
}
//转换为稀疏数组
int sum = 0;
for (int i = 0; i < 11; i++) {
for (int j = 0; j < 11; j++) {
if (array[i][j]!=0){
sum++;
}
}
}
System.out.println("有效的个数"+sum);
//2创建一个稀疏数组的数组
int[][] array2 = new int [sum+1][3];
array2[0][0] = 11;
array2[0][1] = 11;
array2[0][2] = sum;
//遍历二维数组,将非零的数,存放在稀疏数组中
int count = 0;
for (int i = 0; i < array.length; i++) {
for (int j = 0; j < array[i].length; j++) {
if (array[i][j]!=0){
count++;
array2[count][0]=i;
array2[count][1]=j;
array2[count][2]=array[i][j];
}
}
}
//输出稀疏数组
for (int i = 0; i < array2.length; i++) {
System.out.println(array2[i][0]+"/t"
+array2[i][1]+"/t"
+array2[i][2]+"/t");
}
//1读取系数数组的值
int[][] array3 =new int[array2[0][0]][array2[0][1]];
//2给其中的元素还原值
for (int i = 1; i < array2.length; i++) {
array3[array2[i][0]][array2[i][1]] = array2[i][2];
}
//3打印
System.out.println("输出还原数组");
for (int[] ints : array3){
for (int anInt : ints) {
System.out.print(anInt+"/t");
}
System.out.println();
}
}
}
原创文章,作者:,如若转载,请注明出处:https://blog.ytso.com/277860.html