04-MyBatisPlus条件构造器


一、wapper介绍

image

Wrapper : 条件构造抽象类,最顶端父类
    AbstractWrapper : 用于查询条件封装,生成 sql 的 where 条件
        QueryWrapper : Entity 对象封装操作类,不是用lambda语法
        UpdateWrapper : Update 条件封装,用于Entity对象更新操作
    AbstractLambdaWrapper : Lambda 语法使用 Wrapper统一处理解析 lambda 获取 column。
        LambdaQueryWrapper :看名称也能明白就是用于Lambda语法使用的查询Wrapper
        LambdaUpdateWrapper : Lambda 更新封装Wrapper
@RunWith(SpringRunner.class)
@SpringBootTest
public class QueryWrapperTests {

    @Autowired
    private UserMapper userMapper;
}

二、AbstractWrapper

注意:以下条件构造器的方法入参中的 column 均表示数据库字段

1、ge、gt、le、lt、isNull、isNotNull

@Test
public void testDelete() {

    QueryWrapper<User> queryWrapper = new QueryWrapper<>();
    queryWrapper
        .isNull("name")
        .ge("age", 12)
        .isNotNull("email");
    int result = userMapper.delete(queryWrapper);
    System.out.println("delete return count = " + result);
}

SQL:UPDATE user SET deleted=1 WHERE deleted=0 AND name IS NULL AND age >= ? AND email IS NOT NULL

2、eq、ne

注意:seletOne返回的是一条实体记录,当出现多条时会报错

@Test
public void testSelectOne() {

    QueryWrapper<User> queryWrapper = new QueryWrapper<>();
    queryWrapper.eq("name", "Tom");

    User user = userMapper.selectOne(queryWrapper);
    System.out.println(user);
}

SELECT id,name,age,email,create_time,update_time,deleted,version FROM user WHERE deleted=0 AND name = ?

3、between、notBetween

包含大小边界

@Test
public void testSelectCount() {

    QueryWrapper<User> queryWrapper = new QueryWrapper<>();
    queryWrapper.between("age", 20, 30);

    Integer count = userMapper.selectCount(queryWrapper);
    System.out.println(count);
}

SELECT COUNT(1) FROM user WHERE deleted=0 AND age BETWEEN ? AND ?

4、allEq

@Test
public void testSelectList() {

    QueryWrapper<User> queryWrapper = new QueryWrapper<>();
    Map<String, Object> map = new HashMap<>();
    map.put("id", 2);
    map.put("name", "Jack");
    map.put("age", 20);

    queryWrapper.allEq(map);
    List<User> users = userMapper.selectList(queryWrapper);

    users.forEach(System.out::println);
}


SELECT id,name,age,email,create_time,update_time,deleted,version FROM user WHERE deleted=0 AND name = ? AND id = ? AND age = ?

5、like、notLike、likeLeft、likeRight

selectMaps返回Map集合列表

@Test
public void testSelectMaps() {

    QueryWrapper<User> queryWrapper = new QueryWrapper<>();
    queryWrapper
        .notLike("name", "e")
        .likeRight("email", "t");

    List<Map<String, Object>> maps = userMapper.selectMaps(queryWrapper);//返回值是Map列表
    maps.forEach(System.out::println);
}

SELECT id,name,age,email,create_time,update_time,deleted,version
FROM user WHERE deleted=0 AND name NOT LIKE ? AND email LIKE ?

6、in、notIn、inSql、notinSql、exists、notExists

in、notIn:

  • notIn(“age”,{1,2,3})—>age not in (1,2,3)
  • notIn(“age”, 1, 2, 3)—>age not in (1,2,3)
    inSql、notinSql:可以实现子查询
  • 例: inSql(“age”, “1,2,3,4,5,6”)—>age in (1,2,3,4,5,6)
  • 例: inSql(“id”, “select id from table where id < 3”)—>id in (select id from table where id < 3)
@Test
public void testSelectObjs() {

    QueryWrapper<User> queryWrapper = new QueryWrapper<>();
    //queryWrapper.in("id", 1, 2, 3);
    queryWrapper.inSql("id", "select id from user where id < 3");

    List<Object> objects = userMapper.selectObjs(queryWrapper);//返回值是Object列表
    objects.forEach(System.out::println);
}

SELECT id,name,age,email,create_time,update_time,deleted,version
FROM user WHERE deleted=0 AND id IN (select id from user where id < 3)

7、or、and

注意:这里使用的是 UpdateWrapper
不调用or则默认为使用 and 连

@Test
public void testUpdate1() {

    //修改值
    User user = new User();
    user.setAge(99);
    user.setName("Andy");

    //修改条件
    UpdateWrapper<User> userUpdateWrapper = new UpdateWrapper<>();
    userUpdateWrapper
        .like("name", "h")
        .or()
        .between("age", 20, 30);

    int result = userMapper.update(user, userUpdateWrapper);

    System.out.println(result);
}

UPDATE user SET name=?, age=?, update_time=? WHERE deleted=0 AND name LIKE ? OR age BETWEEN ? AND ?

8、嵌套or、嵌套and

这里使用了lambda表达式,or中的表达式最后翻译成sql时会被加上圆括号

@Test
public void testUpdate2() {

    //修改值
    User user = new User();
    user.setAge(99);
    user.setName("Andy");

    //修改条件
    UpdateWrapper<User> userUpdateWrapper = new UpdateWrapper<>();
    userUpdateWrapper
        .like("name", "h")
        .or(i -> i.eq("name", "李白").ne("age", 20));

    int result = userMapper.update(user, userUpdateWrapper);

    System.out.println(result);
}

UPDATE user SET name=?, age=?, update_time=?
WHERE deleted=0 AND name LIKE ?
OR ( name = ? AND age <> ? )

9、orderBy、orderByDesc、orderByAsc

@Test
public void testSelectListOrderBy() {

    QueryWrapper<User> queryWrapper = new QueryWrapper<>();
    queryWrapper.orderByDesc("id");

    List<User> users = userMapper.selectList(queryWrapper);
    users.forEach(System.out::println);
}

SELECT id,name,age,email,create_time,update_time,deleted,version
FROM user WHERE deleted=0 ORDER BY id DESC

10、last

直接拼接到 sql 的最后
注意:只能调用一次,多次调用以最后一次为准 有sql注入的风险,请谨慎使用

@Test
public void testSelectListLast() {

    QueryWrapper<User> queryWrapper = new QueryWrapper<>();
    queryWrapper.last("limit 1");

    List<User> users = userMapper.selectList(queryWrapper);
    users.forEach(System.out::println);
}

SELECT id,name,age,email,create_time,update_time,deleted,version
FROM user WHERE deleted=0
limit 1

11、指定要查询的列

@Test
public void testSelectListColumn() {
    QueryWrapper<User> queryWrapper = new QueryWrapper<>();
    queryWrapper.select("id", "name", "age");

    List<User> users = userMapper.selectList(queryWrapper);
    users.forEach(System.out::println);
}

SELECT id,name,age FROM user WHERE deleted=0

12、set、setSql

最终的sql会合并 user.setAge(),以及 userUpdateWrapper.set() 和 setSql() 中 的字段

@Test
public void testUpdateSet() {

    //修改值
    User user = new User();
    user.setAge(99);

    //修改条件
    UpdateWrapper<User> userUpdateWrapper = new UpdateWrapper<>();
    userUpdateWrapper
        .like("name", "h")
        .set("name", "老李头")//除了可以查询还可以使用set设置修改的字段
        .setSql(" email = '123@qq.com'");//可以有子查询

    int result = userMapper.update(user, userUpdateWrapper);
}

UPDATE user SET age=?, update_time=?, name=?, email = ‘123@qq.com’ WHERE deleted=0 AND name LIKE ?

原创文章,作者:ItWorker,如若转载,请注明出处:https://blog.ytso.com/289117.html

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