let arr1 = [1,2,7,4,9,5,3,2]
let arr2 = [2,3,5,6]
//去重利用集合，并返回数组
let uniq = [...new Set(arr1)]
console.log(uniq);
//求交集
let jiaoji = arr2.filter(item=>uniq.includes(item))
console.log(jiaoji)
//求并集
let bingji = new Set([...arr1 , ...arr2]);
console.log(bingji)
//求差集
let chaji = arr2.filter(item=>!(uniq.includes(item)) )
console.log(chaji)
原创文章，作者：ItWorker，如若转载，请注明出处：https://blog.ytso.com/289853.html