python 时间处理详解编程语言

在实际中遇到一个时间处理问题，需要将 Sep 06, 2014 19:30 （UTC 时间） 和 当前时间比较早晚，知道 此 2014-09-06 19:30 格式时间的运算。因此，在处理时，就想

先将sep 格式时间转化成 后面一个格式的时间样子，没有找到相关函数，于是自己简单的写了个程序，仅记于此，以备查询

代码如下：

# -*- coding: utf-8 -*-  
from datetime import date 
from datetime import datetime 
from datetime import timedelta 
   
# # #如果是返回当前时间，可以简单的写成 
# # time.localtime() 
# # #这个返回UTC时间 
# # time.gmtime() 
# lt = time.localtime() 
# tm = time.gmtime() 
# ft = time.strftime('%Y-%m-%d %H-%M',lt) 
# ft2 = time.strftime('%Y-%m-%d %H:%M',tm) 
# print ft, ft2 
# print '--------------------------------------------------------' 
# now = datetime.datetime.now() 
# now = now.replace(day = 1) 
# print now 
# print now.time() 
# 
# mytime = ['2014-09-06 20:19'] 
# #mytime2 = '2014-10-09 14:32' 
# str = "".join(mytime) 
# print str 
# retime  = datetime.strptime(str,'%Y-%m-%d %H:%M') 
# print retime 
# retime = retime +timedelta(hours = 8) 
# print retime 
# 
# tdtime = datetime.now() 
# print tdtime 
# if retime <= tdtime - timedelta(days = 7): 
#     print "too early" 
# 
# #Sep 06, 2014 19:30 
   
monthdic = {'Jan':'01', 'Feb':'02', 'Mar':'03', 'Apr':'04', 'May':'05', 'Jun':'06', 'Jul':'07', 'Aug':'08', 'Sep':'09', 'Oct':'10', 'Nov':'11', 'Dec':'12'} 
def time_format(timestr): 
    timestr = timestr.replace(',','') 
    #print timestr 
    timelist = timestr.split() 
    #print timelist 
    mon = "".join(timelist[0]) 
    #print  mon 
    timelist[0] = monthdic[mon] 
    #print timelist 
    mytime = "".join(timelist[2])+'-'+"".join(timelist[0])+'-'+"".join(timelist[1])+' '+ "".join(timelist[3]) 
    return mytime 
if __name__ == '__main__': 
    timestr = 'Sep 06, 2014 19:30' 
    str = time_format(timestr) 
    print str       
    mytime  = datetime.strptime(str,'%Y-%m-%d %H:%M')  
    print mytime 
    mytime = mytime +timedelta(hours = 8) 
    print mytime   
    tdtime = datetime.now() 
    print tdtime 
    if mytime <= tdtime - timedelta(days = 7): 
        print "too early"