身份证校验详解编程语言

function IdentityCodeValid(code) {

        var city={11:”北京”,12:”天津”,13:”河北”,14:”山西”,15:”内蒙古”,21:”辽宁”,22:”吉林”,23:”黑龙江 “,31:”上海”,32:”江苏”,33:”浙江”,34:”安徽”,35:”福建”,36:”江西”,37:”山东”,41:”河南”,42:”湖北 “,43:”湖南”,44:”广东”,45:”广西”,46:”海南”,50:”重庆”,51:”四川”,52:”贵州”,53:”云南”,54:”西藏 “,61:”陕西”,62:”甘肃”,63:”青海”,64:”宁夏”,65:”新疆”,71:”台湾”,81:”香港”,82:”澳门”,91:”国外 “};

        var tip = “”;

        var pass= true;

        

        if(!code || !/^/d{6}(18|19|20)?/d{2}(0[1-9]|1[12])(0[1-9]|[12]/d|3[01])/d{3}(/d|X)$/i.test(code)){

            tip = “身份证号格式错误”;

            pass = false;

        }

        

       else if(!city[code.substr(0,2)]){

            tip = “地址编码错误”;

            pass = false;

        }

        else{

            //18位身份证需要验证最后一位校验位

            if(code.length == 18){

                code = code.split(”);

                //∑(ai×Wi)(mod 11)

                //加权因子

                var factor = [ 7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2 ];

                //校验位

                var parity = [ 1, 0, ‘X’, 9, 8, 7, 6, 5, 4, 3, 2 ];

                var sum = 0;

                var ai = 0;

                var wi = 0;

                for (var i = 0; i < 17; i++)

                {

                    ai = code[i];

                    wi = factor[i];

                    sum += ai * wi;

                }

                var last = parity[sum % 11];

                if(parity[sum % 11] != code[17]){

                    tip = “校验位错误”;

                    pass =false;

                }

            }

        }

        if(!pass) alert(tip);

        return pass;

    }

var c = ‘440881198506201695’;
    var res= IdentityCodeValid(c);
    console.log(res);

原创文章,作者:ItWorker,如若转载,请注明出处:https://blog.ytso.com/8782.html

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