220728
题目
原始数据如下：
| Carrier_Name | OrderNumber | ReSumCost |
|---|---|---|
| 临时 | JOY19080300003 | 170.00 |
| 张三 | JOY19080300003 | 170.00 |
| 临时 | JOY19080300004 | 196.50 |
| 张三 | JOY19080300004 | 196.50 |
| 临时 | JOY19080300006 | 458.80 |
| 张三 | JOY19080300006 | 458.80 |
| 李四 | JOY19080300007 | 272.00 |
| 李四 | JOY19080300008 | 315.00 |
| 临时 | JOY19080300008 | 315.00 |
相同OrderNumber只取一条ReSumCost的结果，希望得到：
| Carrier_Name | OrderNumber | ReSumCost | NewReSumCost |
|---|---|---|---|
| 临时 | JOY19080300003 | 170.00 | 170.00 |
| 张三 | JOY19080300003 | 170.00 | 0.00 |
| 临时 | JOY19080300004 | 196.50 | 196.50 |
| 张三 | JOY19080300004 | 196.50 | 0.00 |
| 临时 | JOY19080300006 | 458.80 | 458.80 |
| 张三 | JOY19080300006 | 458.80 | 0.00 |
| 李四 | JOY19080300007 | 272.00 | 272.00 |
| 李四 | JOY19080300008 | 315.00 | 315.00 |
| 临时 | JOY19080300008 | 315.00 | 0.00 |
数据脚本
CREATE TABLE F0728
(
Carrier_Name NVARCHAR(10) NOT NULL,
OrderNumber VARCHAR(20) NOT NULL,
ReSumCost DECIMAL(10, 2) NOT NULL
);
INSERT INTO F0728 VALUES('临时', 'JOY19080300003', 170);
INSERT INTO F0728 VALUES('张三', 'JOY19080300003', 170);
INSERT INTO F0728 VALUES('临时', 'JOY19080300004', 196.5);
INSERT INTO F0728 VALUES('张三', 'JOY19080300004', 196.5);
INSERT INTO F0728 VALUES('临时', 'JOY19080300006', 458.8);
INSERT INTO F0728 VALUES('张三', 'JOY19080300006', 458.8);
INSERT INTO F0728 VALUES('李四', 'JOY19080300007', 272);
INSERT INTO F0728 VALUES('李四', 'JOY19080300008', 315);
INSERT INTO F0728 VALUES('临时', 'JOY19080300008', 315);
我的答案
参考答案
select *,
IF(LAG(OrderNumber)
over (partition by OrderNumber order by OrderNumber) = OrderNumber
, 0, ReSumCost) NewReSumCost
from f0728;
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