#include <stdio.h>
int main () {
/* an array with 5 elements */
double balance[5] = {1000.0, 2.0, 3.4, 17.0, 50.0};
double *p;
int i;
p = balance;
/* output each array element's value */
printf( "Array values using pointer/n");
for ( i = 0; i < 5; i++ ) {
printf("*(p + %d) : %f/n", i, *(p + i) );
}
printf( "Array values using balance as address/n");
for ( i = 0; i < 5; i++ ) {
printf("*(balance + %d) : %f/n", i, *(balance + i) );
}
return 0;
}
原创文章，作者：ItWorker，如若转载，请注明出处：https://blog.ytso.com/tech/pnotes/265142.html