#include <stdio.h>
double power(double n, int p); // ANSI prototype
int main(void)
{
double x, xpow;
int exp;//w w w . jav a2 s. co m
printf("Enter two numbers. Enter q to quit./n");
while (scanf("%lf%d", &x, &exp) == 2){
xpow = power(x,exp); // function call
printf("%.3g to the power %d is %.5g/n", x, exp, xpow);
printf("Enter next pair of numbers or q to quit./n");
}
printf("from yi ibai.com!/n");
return 0;
}
double power(double n, int p) {
double pow = 1;
int i;
for (i = 1; i <= p; i++)
pow *= n;
return pow; // return the value of pow
}
原创文章，作者：ItWorker，如若转载，请注明出处：https://blog.ytso.com/tech/pnotes/266556.html