#include <stdio.h>
int main(void)
{
char first = 'A';
char second = 'B';
char last = 'Z';
char number = 40;
char ex1 = first + 2; // Add 2 to 'A'
char ex2 = second - 1; // Subtract 1 from 'B'
char ex3 = last + 2; // Add 2 to 'Z'
printf("Character values %-5c%-5c%-5c/n", ex1, ex2, ex3);
printf("Numerical equivalents %-5d%-5d%-5d/n", ex1, ex2, ex3);
printf("The number %d is the code for the character %c/n", number, number);
return 0;
}
原创文章，作者：ItWorker，如若转载，请注明出处：https://blog.ytso.com/tech/pnotes/266601.html