codewars联系题

You are the “computer expert” of a local Athletic Association (C.A.A.). Many teams of runners come to compete. Each time you get a string of all race results of every team who has run. For example here is a string showing the individual results of a team of 5 runners:

"01|15|59, 1|47|6, 01|17|20, 1|32|34, 2|3|17"

Each part of the string is of the form: h|m|s where h, m, s (h for hour, m for minutes, s for seconds) are positive or null integer (represented as strings) with one or two digits. Substrings in the input string are separated by , or ,.

To compare the results of the teams you are asked for giving three statistics; range, average and median.

• Range : difference between the lowest and highest values. In {4, 6, 9, 3, 7} the lowest value is 3, and the highest is 9, so the range is 9 − 3 = 6.

• Mean or Average : To calculate mean, add together all of the numbers in a set and then divide the sum by the total count of numbers.

• Median : In statistics, the median is the number separating the higher half of a data sample from the lower half. The median of a finite list of numbers can be found by arranging all the observations from lowest value to highest value and picking the middle one (e.g., the median of {3, 3, 5, 9, 11} is 5) when there is an odd number of observations. If there is an even number of observations, then there is no single middle value; the median is then defined to be the mean of the two middle values (the median of {3, 5, 6, 9} is (5 + 6) / 2 = 5.5).

Your task is to return a string giving these 3 values. For the example given above, the string result will be

"Range: 00|47|18 Average: 01|35|15 Median: 01|32|34"

of the form: “Range: hh|mm|ss Average: hh|mm|ss Median: hh|mm|ss”`

where hh, mm, ss are integers (represented by strings) with each 2 digits.

Remarks:

1. if a result in seconds is ab.xy… it will be given truncated as ab.
2. if the given string is “” you will return “

#!/bin/bash
stat () {
    num=`echo $1 | awk -F "," '{print NF}'` 
    i=0
    sum=0
    
    ch_time () {
    let a=$1%60
    let b=$1/60%60
    let c=$1/3600
    ss=`printf "%02d/n" $a`
    mm=`printf "%02d/n" $b`
    hh=`printf "%02d/n" $c`
    echo "$hh|$mm|$ss"
    }
    
    
    for time in `echo $1 | sed s/,//g`
    do
      hh=`echo $time | awk -F'|' '{print$1}'`
      mm=`echo $time | awk -F'|' '{print$2}'`
      ss=`echo $time | awk -F'|' '{print$3}'`
      let time_list[i]=hh*3600+mm*60+ss
      let sum=sum+time_list[i]
      let i++
    done

    new_time_list=(`echo ${time_list[*]}| tr ' ' '/n'|sort -n`)
    let range=new_time_list[-1]-new_time_list[0]
    let average=sum/num
    let rem=num%2
    
    if [ $rem -eq 0 ];then
      let mid=$num/2+1
      let mid_2=$num/2
      let median=(${new_time_list[mid]}+${new_time_list[mid_2]})/2
    else
      let mid=$num/2
      let median=${new_time_list[mid]}
    fi

    Range=`ch_time $range`
    Average=`ch_time $average`
    Median=`ch_time $median`
    echo "Range: $Range Average: $Average Median: $Median"   
}
stat "$1"