JAVA集合stream操作

import lombok.*;

import java.util.*;
import java.util.stream.Collectors;

import static java.util.Comparator.comparing;
import static java.util.stream.Collectors.*;

public class CollectionStreamMethod {

    @AllArgsConstructor
    @NoArgsConstructor
    @Getter @Setter
    static class Student{
        String name;
        String sex;
        Integer age;
    }

    public static void main(String[] args) {
        List<Student> list = new ArrayList();
        list.add(new Student("小明", "男", 18));
        list.add(new Student("小刚", "男", 20));
        list.add(new Student("小雅", "女", 19));
        list.add(new Student("小敏", "女", 22));
        list.add(new Student("小伟", "男", 24));
        list.add(new Student("小欣", "女", 21));
        list.add(new Student("小丽", "女", 25));
        list.add(new Student("小悦", "女", 21));

        //求性别为男的学生集合
        List<Student> l1 = list.stream().filter(student -> student.sex.equals("男")).collect(toList());

        //map的key值true为男，false为女的集合
        Map<Boolean, List<Student>> map1 = list.stream().collect(partitioningBy(student -> student.getSex().equals("男")));

        //求性别为男的学生总岁数
        Integer sum = list.stream().filter(student -> student.sex.equals("男")).mapToInt(Student::getAge).sum();

        //按性别进行分组统计人数
        Map<String, Integer> map = list.stream().collect(groupingBy(Student::getSex, Collectors.summingInt(p -> 1)));

        //判断是否有年龄大于25岁的学生
        boolean check = list.stream().anyMatch(student -> student.getAge() > 25);

        //获取所有学生的姓名集合
        List<String> l2 = list.stream().map(Student::getName).collect(toList());

        //求所有人的平均年龄
        double avg = list.stream().collect(averagingInt(Student::getAge));

        //求年龄最大的学生
        Student s = list.stream().reduce((student, student2) -> student.getAge() > student2.getAge() ? student:student2).get();

        Student stu = list.stream().collect(maxBy(comparing(Student::getAge))).get();

        //排序
        //按照年龄从小到大排序
        List<Student> l3 = list.stream().sorted((s1, s2) -> s1.getAge().compareTo(s2.getAge())).collect(toList());
        //求年龄最小的两个学生
        List<Student> l4 = l3.stream().limit(2).collect(toList());
        //返回 对象集合以类属性一升序排序
        list.stream().sorted(comparing(Student::getAge));
        //返回 对象集合以类属性一降序排序 注意两种写法
        //先以属性一升序,结果进行属性一降序
        list.stream().sorted(comparing(Student::getAge).reversed());
        //以属性一降序
        list.stream().sorted(comparing(Student::getAge,Comparator.reverseOrder()));
        //返回 对象集合以类属性一升序 属性二升序
        list.stream().sorted(comparing(Student::getAge).thenComparing(Student::getName));
        //返回 对象集合以类属性一降序 属性二升序 注意两种写法
        //先以属性一升序,升序结果进行属性一降序,再进行属性二升序
        list.stream().sorted(comparing(Student::getAge).reversed().thenComparing(Student::getName));
        //先以属性一降序,再进行属性二升序
        list.stream().sorted(comparing(Student::getAge,Comparator.reverseOrder()).thenComparing(Student::getName));
        //返回 对象集合以类属性一降序 属性二降序 注意两种写法
        //先以属性一升序,升序结果进行属性一降序,再进行属性二降序
        list.stream().sorted(comparing(Student::getAge).reversed().thenComparing(Student::getName,Comparator.reverseOrder()));
        //先以属性一降序,再进行属性二降序
        list.stream().sorted(comparing(Student::getAge,Comparator.reverseOrder()).thenComparing(Student::getName,Comparator.reverseOrder()));
        //返回 对象集合以类属性一升序 属性二降序 注意两种写法
        //先以属性一升序,升序结果进行属性一降序,再进行属性二升序,结果进行属性一降序属性二降序
        list.stream().sorted(comparing(Student::getAge).reversed().thenComparing(Student::getName).reversed());
        //先以属性一升序,再进行属性二降序
        list.stream().sorted(comparing(Student::getAge).thenComparing(Student::getName,Comparator.reverseOrder()));

        //获取所有的名字，组成一条语句
        String str = list.stream().map(Student::getName).collect(Collectors.joining(",", "[", "]"));

        //获取年龄的最大值、最小值、平均值、求和等等
        IntSummaryStatistics intSummaryStatistics = list.stream().mapToInt(Student::getAge).summaryStatistics();
        System.out.println(intSummaryStatistics.getMax());
        System.out.println(intSummaryStatistics.getCount());
    }

}