jQuery实现密码强度检测，以破解时间来衡量详解编程语言

[JavaScript]代码    

(function($){  
     $.fn.extend({   
         pwdstr: function(el) {			 
			return this.each(function() { 
					 
					 
					 
					$(this).keyup(function(){ 
						$(el).html(getTime($(this).val())); 
					}); 
					 
					function getTime(str){ 
					 
					var chars = 0; 
					var rate = 2800000000; 
					 
					if((/[a-z]/).test(str)) chars +=  26; 
					if((/[A-Z]/).test(str)) chars +=  26; 
					if((/[0-9]/).test(str)) chars +=  10; 
					if((/[^a-zA-Z0-9]/).test(str)) chars +=  32; 
 
					var pos = Math.pow(chars,str.length); 
					var s = pos/rate; 
					 
					var decimalYears = s/(3600*24*365); 
					var years = Math.floor(decimalYears); 
					 
					var decimalMonths =(decimalYears-years)*12; 
					var months = Math.floor(decimalMonths); 
					 
					var decimalDays = (decimalMonths-months)*30; 
					var days = Math.floor(decimalDays); 
					 
					var decimalHours = (decimalDays-days)*24; 
					var hours = Math.floor(decimalHours); 
					 
					var decimalMinutes = (decimalHours-hours)*60; 
					var minutes = Math.floor(decimalMinutes); 
					 
					var decimalSeconds = (decimalMinutes-minutes)*60; 
					var seconds = Math.floor(decimalSeconds); 
					 
					var time = []; 
					 
					if(years > 0){ 
						if(years == 1) 
							time.push("1 year, "); 
						else 
							time.push(years + " years, "); 
					} 
					if(months > 0){ 
						if(months == 1) 
							time.push("1 month, "); 
						else 
							time.push(months + " months, "); 
					} 
					if(days > 0){ 
						if(days == 1) 
							time.push("1 day, "); 
				 		else 
							time.push(days + " days, "); 
					} 
					if(hours > 0){ 
						if(hours == 1) 
							time.push("1 hour, "); 
						else 
							time.push(hours + " hours, "); 
					} 
					if(minutes > 0){ 
						if(minutes == 1) 
							time.push("1 minute, "); 
						else 
							time.push(minutes + " minutes, "); 
					} 
					if(seconds > 0){ 
						if(seconds == 1) 
							time.push("1 second, "); 
						else 
							time.push(seconds + " seconds, "); 
					} 
					 
					if(time.length <= 0) 
						time = "less than one second, "; 
					else if(time.length == 1) 
						time = time[0]; 
					else 
						time = time[0] + time[1]; 
 
					 return time.substring(0,time.length-2); 
					} 
					 
			 }); 
        }  
    });  
})(jQuery);