#include <stdio.h>
int main(void){
int i = 0;
int j = 0;
int value_count = 0;
float fp1 = 0.0f;
printf("Enter: fp1 = 3.14159 i = 7 8/n");
printf("/nInput:");
value_count = scanf("fp1 = %f i = %d %d", &fp1, &i , &j);
printf("/nOutput:/n");
printf("Count of values read = %d/n", value_count);
printf("fp1 = %f/ti = %d/tj = %d/n", fp1, i, j);
return 0;
}
原创文章,作者:ItWorker,如若转载,请注明出处:https://blog.ytso.com/266497.html