https://www.luogu.com.cn/problem/P3375
- 获得next数组(最长公共前后缀)
- 用类似的方法获得进行kmp操作
- 每次匹配成功匹配下一个时 有(j=next[j])
#include <bits/stdc++.h>
using namespace std;
#define MAX 10000000
char a[MAX], b[MAX];
int nexts[MAX];
int len_b, len_a;
void input()
{
scanf("%s", a + 1);
scanf("%s", b + 1);
}
void getnext()
{
int j = 0;
len_b = strlen(b + 1);
for (int i = 2; i <= len_b; i++)
{
while (j && b[j + 1] != b[i])
{
j = nexts[j];
}
if (b[j + 1] == b[i])
{
j++;
}
nexts[i] = j;
}
}
void KMP()
{
int j = 0;
len_a = strlen(a + 1);
for (int i = 1; i <= len_a; i++)
{
while (j && a[i] != b[j + 1])
{
j = nexts[j];
}
if (a[i] == b[j + 1])
{
j++;
}
if (j == len_b)
{
printf("%d/n", i + 1 - j);
j = nexts[j];
}
}
for (int i = 1; i <= len_b; i++)
{
printf("%d ", nexts[i]);
}
}
int main()
{
input();
getnext();
KMP();
}
原创文章,作者:,如若转载,请注明出处:https://blog.ytso.com/tech/pnotes/277985.html